display input form if custom field is not set WordPress

Kyle answers:

There is obviously more work required if you want to actually submit the entry, and update the post based on the submission. Here is the part you are looking for though:

function display_form(){

global $post;

$your_field = get_post_meta($post->ID, 'your-custom-field', TRUE);

if (empty($your_field)){

echo '<form><input class="input-text"><br><input type="button" value="submit" /></form>' ;

}else{

echo $your_field;

}}

Sébastien | French WordpressDesigner answers:

the name of your custom field is "setting" for example

if (get_post_meta($post->ID, "settings", true) == 0) {
echo "here is my content";
} else {
echo "no content here";
}


phppoet answers:

Put this code in main output file . try it and tell me if there is any error. I m here to help you.




global $post;

$custom_field= get_post_meta($post->ID, 'your-custom-field', TRUE);

if (!isset($custom_field)) {

?> <form>

//Enter the form code here //

</form>
<?php
}else { the_content();
}

Arnav Joy answers:

try this

<?php

$custom_fields = array('field1','field2','field3');
$current_page_id = get_the_ID();

if( $_POST['submit']){
foreach( $custom_fields as $cf ) {
if( $_POST[$cf] != '' )
update_post_meta( $current_page_id , $cf , $_POST[$cf] );
}

}

?>


<form method="post" action="<?php echo get_permalink($current_page_id);?>">
<?php
foreach( $custom_fields as $cf ) {
$custom_field_value = '';

$custom_field_value = get_post_meta($current_page_id,$cf,true);

if( !empty($custom_field_value) )
echo 'Field '.$cf.' has value = '.$custom_field_value.'<br>';
else
echo '<input type="text" name="'.$cf.'" >' ;
}

?>

<input type="submit" name="submit" />
</form>