Jquery open popbox if gform fails WordPress

Christianto answers:

Hi Kyle,

Please try my code, I use cookie to remember the last clicked popbox for the form element.
Replace your code to start the popbox

jQuery(document).ready(function(){
jQuery('.popbox').popbox();
});

/**
* jQuery Cookie
*/
(function(e,t,n){function i(e){return e}function s(e){return decodeURIComponent(e.replace(r," "))}var r=/\+/g;var o=e.cookie=function(r,u,a){if(u!==n){a=e.extend({},o.defaults,a);if(u===null){a.expires=-1}if(typeof a.expires==="number"){var f=a.expires,l=a.expires=new Date;l.setDate(l.getDate()+f)}u=o.json?JSON.stringify(u):String(u);return t.cookie=[encodeURIComponent(r),"=",o.raw?u:encodeURIComponent(u),a.expires?"; expires="+a.expires.toUTCString():"",a.path?"; path="+a.path:"",a.domain?"; domain="+a.domain:"",a.secure?"; secure":""].join("")}var c=o.raw?i:s;var h=t.cookie.split("; ");for(var p=0,d=h.length;p<d;p++){var v=h[p].split("=");if(c(v.shift())===r){var m=c(v.join("="));return o.json?JSON.parse(m):m}}return null};o.defaults={};e.removeCookie=function(t,n){if(e.cookie(t)!==null){e.cookie(t,null,n);return true}return false}})(jQuery,document);
//*** End jQuery Cookie ***

jQuery(document).ready(function($){
var ele = $('.popbox');

/* initialize popbox */
ele.popbox();

/* save clicked index popbox that contain the form */
ele.each(function(index){
$(this).find('.open').click(function(e){
e.preventDefault();
$.cookie('pb_index', index);
});
});

var pb_index = $.cookie('pb_index');
if($('.gform_validation_error').length > 0 && pb_index != 'none'){

// find the form by looking at cookie and open it
ele.eq(pb_index).attr('id','to-this').find('.open').click();

// go to the marked error form
window.location.hash = 'to-this';

// clean up cookie and id
$.cookie('pb_index', 'none');
$('.popbox').removeAttr('id');

}
});

It will open the form if error exists, base on last saved popbox index.
Optionally you can separate the jQuery cookie to separate js file instead of including it inline..

---

---

---

---

---