Conditional IF /ELSE statements with taxonomy WordPress
- SOLVED
I've been trying to get a conditional if/else statement within a single post to work. I have a taxonomy of 'artist' and I would like posts with the value of 'various-artists' to display differently than other values. Here is the code I've working with:
<?php if ( artist( 'various-artists' ) ) {
echo '<h2>Various Artists</h2>';
} else {
echo '<h2><?php echo get_the_term_list( $post->ID, 'artist' ); ?></h2>'; } ?>
Thank you for your answers and please let me know if you need any other info.
Answers (3)
Ivaylo Draganov answers:
Hi,
there's an undocumented function for checking whether a post has a specific term. Here's how I've tweaked your code:
<?php
if ( has_term( 'various-artists', 'artist', $post->ID ) ) {
echo '<h2>Various Artists</h2>';
} else {
echo '<h2>' . get_the_term_list( $post->ID, 'artist' ) . '</h2>';
}
?>
Use that in the loop. Let me know how it went :)
Jeremy Phillips comments:
That did the job beautifully! Thanks a lot!
Michael Fields answers:
Something like this should work inside the loop:
<?php
$terms = get_the_terms( get_the_ID(), 'artist' );
if ( is_array( $terms ) && in_array( 'various-artists', $terms ) ) {
print '<h2>Various Artists</h2>';
}
else {
print '<h2>' . get_the_term_list( get_the_ID(), 'artist' ) . '</h2>';
}
?>
Maor Barazany answers:
<?php
global $post;
$post_terms = get_the_terms($post->ID, 'artist'); //get array of artists taxonomy objects
//now we will make array with terms from this taxonomy of this post
foreach($post_terms as $t) {
$termname[] = $t->name;
}
//now we can check the term we want with that array we created
if (in_array('various-artists',$termname) {
echo '<h2>Various Artists</h2>';
} else {
echo '<h2><?php echo get_the_term_list( $post->ID, 'artist' ); ?></h2>'; } ?>